(0.0K) (0.0K)
Teachers Notes:
Problem 1: Both the empirical and molecular formulas are CH2O2.
Problem 2: 1.00 μg CH2O2 x (0.000001 g/μg) x (1mole CH2O2/46.0256g CH2O2) x (6.02 x 1023 molecules/mole) = 1.31 x 1016 molecules CH2O2
Problem 3: Both the empirical and molecular formulas are C5H11N.
Problem 4: 0.500mg C5H11N x (0.000001 g/mg) x (1mole C5H11N/85.14g C5H11N) x (6.02 x 1023 molecules/mole) = 3.54 x 1015 molecules C5H11N
Textbook Resources
Chapter Activities
Teacher
Student
Please read our Terms of Use and Privacy Policy before you explore our Web site. To report a technical problem with this Web site, please contact the Web Producer.