Problem 2: 1. Location of the double bond is one possible isomer.
These could include 1-dodecene, 2-dodecene, 3-dodecene, 4-dodecene,
5-dodecene, and 6-dodecene.
(6.0K) (7.0K)
(Hydrogen omitted to simplify the drawing)
2. Branched compounds are a second type of isomer.
3,4 dimethyl, 2-decene (6.0K)
3. Geometric isomers include attached groups on the
carbons the double bond.
3,4 diethyl-3-octene (trans) (7.0K)
3,4 diethyl-3-octene (cis) (8.0K)>
or trans-6-dodecene and cis-6-dodecene
(8.0K) (8.0K)
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